1.1x+4.905x^2=29

Solution for 1.1x+4.905x^2=29 equation:

1.1x+4.905x^2=29

We move all terms to the left:

1.1x+4.905x^2-(29)=0

a = 4.905; b = 1.1; c = -29;
Δ = b2-4ac
Δ = 1.12-4·4.905·(-29)
Δ = 570.19
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.1)-\sqrt{570.19}}{2*4.905}=\frac{-1.1-\sqrt{570.19}}{9.81}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.1)+\sqrt{570.19}}{2*4.905}=\frac{-1.1+\sqrt{570.19}}{9.81}
$